Answer:
(C) 4, 12, 20, 28, 36, 44
Step-by-step explanation:
Given: [tex]a_{1}=4[/tex] and [tex]a_{n}=a_{n-1}+8[/tex]
To find: Find the first six terms of the sequence
Solution: Since, it is given that [tex]a_{1}=4[/tex] and [tex]a_{n}=a_{n-1}+8[/tex], then the first term is 4 and the common difference, d=8.
Thus, the next terms are:
[tex]a_{2}=a_{1}+8=4+8=12[/tex],
[tex]a_{3}=a_{2}+8=12+8=20[/tex],
[tex]a_{4}=a_{3}+8=10+8=28[/tex],
[tex]a_{5}=a_{4}+8=28+8=36[/tex] and
[tex]a_{6}=a_{5}+8=36+8=44[/tex]
Thus, the first six terms of the sequence will be 4, 12, 20, 28, 36, 44.
thus, option C is correct.
