he1yenraqietsyahii he1yenraqietsyahii

13-10-2016
Physics

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Use the dot product to find the magnitude of u if u = 6i - 3j

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HomertheGenius HomertheGenius

19-10-2016

Vector u :
u = 6 i - 3 j
The magnitude of vector u :
| u | = [tex] \sqrt{6 ^{2}+(-3) ^{2} } = \sqrt{36+9}= \\ \sqrt{45}= \sqrt{9*5}=3 \sqrt{5} [/tex]
Answer:
The magnitude of vector u is 3√5.

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