Answer:
H = 34.43 m
Explanation:
Given that,
Initial speed of the object, u = 30 m/s
The angle of projection, [tex]\theta=60^{\circ}[/tex]
We need to find the maximum height reached by the object. Let it is H. Using the formula for maximum height reached by the projectile.
[tex]H=\dfrac{u^2\sin^2\theta}{2g}\\\\H=\dfrac{(30)^2\times \sin^2(60)}{2\times 9.8}\\\\H=34.43\ m[/tex]
So, the maximum height reached by the object is 34.43 m.
