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PLEASE HELP
Complete the proofs below using the most appropriate method, SSS or SAS.
7. Given: AM = CP, CM = GP, C is the midpoint of AG
Prove: A4CM = ACGP
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Reasons
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PLEASE HELP Complete the proofs below using the most appropriate method SSS or SAS 7 Given AM CP CM GP C is the midpoint of AG Prove A4CM ACGP G M Statements Re class=

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answer

AM= CP-given

CM=GP-given

C is the midpoint of AG-given

AC=CG- definition of midpoint

ACM=CGP- SSS

Ver imagen finestbrownskinn22

The complete proof is as follows:

  1. [tex]\mathbf{AM = CP}[/tex] -- Given
  2. [tex]\mathbf{CM = GP}[/tex] -- Given
  3. C is the midpoint of AG -- Given
  4. [tex]\mathbf{AC \cong CG}[/tex] --- Definition of Midpoint
  5. [tex]\mathbf{\triangle ACM \cong \triangle CGP}[/tex] ---- Congruent by SSS

The given parameters are:

  1. [tex]\mathbf{AM = CP}[/tex]
  2. [tex]\mathbf{CM = GP}[/tex]
  3. C is the midpoint of AG

This means that, the above statements would represent the first three blanks, and their respective reason is "Given"

Because of (3), above

4. [tex]\mathbf{AC \cong CG}[/tex] --- midpoint definition

(1), (2) and (4) imply that:

The three sides of both triangles are congruent by SSS

Hence, the last statement would be:

[tex]\mathbf{\triangle ACM \cong \triangle CGP}[/tex] ---- Congruent by SSS

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