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URGENT!!! a media statistics agency reports that the mean number of televisions in a household in a particular country is 2.24 with a standard deviation of 1.38 what is the probability of a random sample of 40 households have a sample mean number of at least 2.55 televisions per household.

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Answer:

0.48173

Step-by-step explanation:

Given that :

Mean (m) = 2.24

Standard deviation (s) = 1.38

Sample size (n) = 40

P(x ≥ 2.55)

Z = (x - m) / (s/sqrt(n))

Z = (2.55 - 2.24) / (1.38 / sqrt(40))

Z = 0.01 / 0.2181971

Z = 0.0458301

P(Z ≥ 0.0458) = 0.48173 ( Z probability calculator)

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