A 30 kg table is pushed forward with a force of 12 N. Friction pushes back with a
force of 5 N. What is the net force?!!

Respuesta :

Answer:

a = 0.23 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces applied [N]

m = mass = 30 [kg]

a = acceleration [m/s²]

Now we can use Newton's second law, with forces pointing to the right as positives and negative forces pointing towards the left.

[tex]12 - 5 = 30*a\\7 = 30*a\\a = 0.23 [m/s^{2} ][/tex]