Answer:
b=20 or b=-20
Step-by-step explanation:
Keep in mind the meanings of the values of the discriminant:
If b^2-4ac=0, then the quadratic will have only 1 solution (double root)
If b^2-4ac<0, then the quadratic will have no real solutions
If b^2-4ac>0, then the quadratic will have 2 unique solutions
In this case, to get one real solution, the discriminant must be set up as b^2-4ac=0. Setting up the equation we get:
b^2-4(4)(25)=0
b^2-400=0
b^2=400
b=20 or b=-20
So the values of b would have to be either 20 or -20
The values of b will cause 4x^2+bx+25=0 to have one real solution is -20 and 20
Given the quadratic equation [tex]4x^2+bx+25= 0[/tex], for this expression to have a real solution, the discriminant must be greater than zero
D > 0
b^2 - 4ac > 0
Given that a = 4, b = b, c = 25
b^2 - 4(4)(25) > 0
b^2 - 400 > 0
b^2 > 400
b > ±20
Hence the values of b will cause 4x^2+bx+25=0 to have one real solution is -20 and 20
Learn more on discriminant here: https://brainly.com/question/24730520
