According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function? f(x) = (x3 – 3x + 1)2 2 roots 3 roots 6 roots 9 roots

Respuesta :

Answer:

The answer is C

Step-by-step explanation:

The roots are −1.87938524, 0.34729635, 1.53208888, −1.87938524, 0.34729635, and  1.53208888. That's 6 roots, which is C.

According to the Fundamental Theorem of Algebra, 6 roots exist for the polynomial function.

What is the fundamental Theorem of Algebra?

Fundamental Theorem of Algebra states that every polynomial equation of degree n with complex number coefficients has n roots, or solutions, in the complex numbers. The roots can have a multiplicity greater than zero.

Given polynomial function

[tex]f(x)=(x^{3}-3x+1 )^{2}[/tex]

It has [tex](x^{3} )^{2}[/tex] term in the given polynomial

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of roots as its degree.

= 3 × 2

= 6

So, 6 roots exist for the polynomial function.

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