Answer:
Graph G
Step-by-step explanation:
The graphs are attached
Given that the oil-well contractor drills a shaft 7 meters deeper into the ground every 2 hours, hence the rate at which the shaft drills = 7 meter / 2 hours = 3.5 meters per hour
Since the drill goes into the ground, hence the rate is negative that is -3.5 meters per secong
The slope (rate of change) of a line (m) is given by:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
a) For graph F, the line passes through the point (0,0) and (10, -20). Hence:
[tex]Slope\ of\ line\ F=\frac{-20-0}{10-0} =-2\ meters\ per\ second[/tex]
b) For graph G, the line passes through the point (0,0) and (10, -70). Hence:
[tex]Slope\ of\ line\ G=\frac{-70-0}{10-0} =-7\ meters\ per\ second[/tex]
c) For graph H, the line passes through the point (0,0) and (10, -35). Hence:
[tex]Slope\ of\ line\ H=\frac{-35-0}{10-0} =-3.5\ meters\ per\ second[/tex]
d) For graph J, the line passes through the point (0,-3.5) and (10, -3.5). Hence:
[tex]Slope\ of\ line\ j=\frac{-3.5-(-3.5)}{10-0} =0\ meters\ per\ second[/tex]
