Answer:
Explanation:
Step one:
given data
the current in each 10.0 Ω
The power supply is 60.0 V.
Required:
current in the series and parallel circuit arrangement
Step two:
The drawing looks like a ladder with 4 rungs.
One rung is a 60-volt battery.
The other 3 rungs are the 3 resistors.
a). The equivalent resistance is the reciprocal of (1/10 + 1/10 + 1/10).
That's the reciprocal of 3/10, or about 0.3ohms.
b). I = V/R = 60 /0.3... = 200 Amperes.
Answer:
for series: i=v/r
V=60volts
R=30ohms (added ohms of the 3 resistors)
i=60volts/30ohms
i=2amps
for parallel: i=v/r1 + v/r2 ...
v=60volts
r1=10
r2=10
r3=10
i=60/10+60/10+60/10
i=6+6+6
i=187
Explanation:
https://phys.libretexts.org/Bookshelves/University_Physics/Book%3A_University_Physics_(OpenStax)/Book%3A_University_Physics_II_-_Thermodynamics_Electricity_and_Magnetism_(OpenStax)/10%3A_Direct-Current_Circuits/10.03%3A_Resistors_in_Series_and_Parallel
