Answer:
The system has of the equation has no solution
Thus,
NO SOLUTION!
Step-by-step explanation:
Given the system of equations
[tex]\begin{bmatrix}y=-6x+2\\ -12x-2y=4\end{bmatrix}[/tex]
Arrange equation variables for elimination
[tex]\begin{bmatrix}y+6x=2\\ -2y-12x=4\end{bmatrix}[/tex]
[tex]\mathrm{Multiply\:}y+6x=2\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:2y+12x=4[/tex]
so
[tex]\begin{bmatrix}2y+12x=4\\ -2y-12x=4\end{bmatrix}[/tex]
adding both equations
[tex]-2y-12x=4[/tex]
[tex]+[/tex]
[tex]\underline{2y+12x=4}[/tex]
[tex]0=8[/tex]
so
[tex]\begin{bmatrix}2y+12x=4\\ 0=8\end{bmatrix}[/tex]
0 = 8 is false, therefore the system has of the equation has no solution
Thus,
NO SOLUTION!
Please also check the attached figure.
