Given that,
The arithmetic sequence is [tex]a_n=17+6(n-1)[/tex]
To find,
The first four terms of the sequence.
Solution,
[tex]a_n=17+6(n-1)[/tex]
Put n = 1
[tex]a_2=17+6(1-1)\\\\=17[/tex]
Put n = 2
[tex]a_2=17+6(2-1)\\\\=23[/tex]
Put n = 3
[tex]a_3=17+6(3-1)\\\\=29[/tex]
Put n = 4
[tex]a_4=17+6(4-1)\\\\=35[/tex]
Hence, first four terms are 17, 23,29,35.