Answer:
3.06 m
Explanation:
Time of fall be t .
h = ut + 1/2 g t² , h is height , u is initial vertical velocity = 0
h = 1/2 g t²
32 = .5 x 9.8 x t²
t = 2.55 s
During this period , diver will move in horizontal direction also .
Horizontal displacement during fall
= horizontal velocity x time
= 1.2 x 2.55
= 3.06 m
