Volume of Sodium metal : 20.454 ml
Further explanation
Reaction(balanced) :
2Na + 2H₂O → 2NaOH + H₂
mass NaOH = 34.5 g
mol NaOH(MW=40 g/mol) :
[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{34.5}{40}\\\\mol=0.8625[/tex]
From the equation, mol ratio of Na : NaOH = 2 : 2, so mol Na=mol NaOH=0.8625
Mass Na (Ar=23 g/mol):
[tex]\tt mass=mol\times MW\\\\mass=0.8625\times 23\\\\mass=19.84~g[/tex]
Volume Na :
[tex]\tt V=\dfrac{m}{\rho}\\\\V=\dfrac{19.84~g}{0.97~g/ml}\\\\V=20.454~ml[/tex]
