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  • 15-12-2020
  • Mathematics
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sheikhomarjobe17 sheikhomarjobe17
  • 15-12-2020

90°+32°=X ( exterior < of a ∆)

90°+32°=X ( exterior < of a ∆) 122°=X

90°+32°=X ( exterior < of a ∆) 122°=XTherefore, X= 122°

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