Answer:
1.5* 10¹⁵ Hz
Explanation:
- In any electromagnetic wave (assuming it's propagating in vacuum), the propagation speed is just c, the speed of light.
- As in any wave, there exists a fixed relationship between speed (c), frequency (f) and wavelength (λ), as follows:
[tex]c = \lambda * f (1)[/tex]
- Since c is an universal constant, we can see that there exists an inverse relationship between λ and f, so if the lower the wavelength, the higher the frequency.
- So, in this case, the highest frequency will be the one associated with the lowest wavelength, i.e., 200 nm.
- Solving for f from (1), replacing by the values, we get:
[tex]f = \frac{c}{\lambda} = \frac{3e8m/s}{200e-9m} = 1.5e15 1/sec = 1.5e15 Hz (2)[/tex]
