Answer:
The correct answer is 1.66 atm ≅ 1.7 atm
Explanation:
Given:
T₁ = -13°C + 273 = 260 K (initial temperature)
T₂ = 15°C + 273 = 288 K (final temperature)
P₁ = 1.5 atm
P₂= ?
We use the mathematical expression of Gay Lussac's Law to calculate P₂, as follows:
P₁/T₁ = P₂/T₂
P₂= P₁/T₁ x T₂ = (1.5 atm)/(260 K) x 288 K = 1.66 atm ≅ 1.7 atm
Since the law says that the temperature of a gas is directly proportional to the pressure, when the temperature is increased, the pressure increases.
