Answer:
11/32
Step-by-step explanation:
Given that:
Red section (R) = 3 ; white section (W) = 3 ; green section (G) = 2
Total Number of sections = 8
Probability of getting the same color on two spins :
Probability = (required outcome / Total possible outcomes)
Either P(RR) or P(WW) or P(GG)
(3/8 * 3/8) + (3/8 * 3/8) + (2/8 * 2/8)
9/64 + 9/64 + 4/64
(9 + 9 + 4) / 64
22 / 64
= 11/32
the probability of getting the same color twice is
[tex]\frac{11}{32}[/tex]
Given :
A spinner is evenly divided into eight sections: three are red, three are white and two are green.
Total of 8 sections.
red=3
white =3
green =2
Probability of getting two red color =[tex]\frac{3}{8} \cdot \frac{3}{8}= \frac{9}{64}[/tex]
Probability of getting two white colors =[tex]\frac{3}{8} \cdot \frac{3}{8}= \frac{9}{64}[/tex]
Probability of getting two green colors=[tex]\frac{2}{8} \cdot \frac{2}{8}= \frac{4}{64}[/tex]
Probability (getting same color twice)=[tex]\frac{9}{64} + \frac{9}{64}+ \frac{4}{64}=\frac{22}{64} =\frac{11}{32}[/tex]
Learn more : brainly.com/question/20988561
