In a right triangle the measure of one acute angle is 4 times the difference of the measure of the other acute angle and 5. Find the measure of each acute angle

Respuesta :

Answer:

The measures are 22 and 68 degrees

Step-by-step explanation:

for a right triangle, the total angle measure gives 90

Let one of the acute angle be x and the other be y

The measure of one of the acute angle is 4 times the the difference of the measure of the other angle and 5

x = 4(y-5)

Also x + y = 90

Put i into ii

4(y-5) + y = 90

4y-20 + y = 90

5y-20 = 90

5y = 90 + 20

5y = 110

y = 110/5

y = 22

But;

x = 4(y-5)

x = 4(22-5)

x = 4(17)

x = 68

The sum of the acute angles in a right-angled triangle is 90.

The acute angles are 22 and 68 degrees

Let the acute angles be x and y, such that:

[tex]\mathbf{y = 4(x - 5)}[/tex]

So, we have:

[tex]\mathbf{x + y = 90}[/tex]

Substitute 4(x - 5) for y

[tex]\mathbf{x + 4(x - 5) = 90}[/tex]

Open brackets

[tex]\mathbf{x + 4x - 20 = 90}[/tex]

Add x and 4x

[tex]\mathbf{5x - 20 = 90}[/tex]

Add 20 to both sides

[tex]\mathbf{5x = 110}[/tex]

Divide both sides by 5

[tex]\mathbf{x = 22}[/tex]

Recall that:

[tex]\mathbf{y = 4(x - 5)}[/tex]

So, we have:

[tex]\mathbf{y = 4(22 - 5)}[/tex]

[tex]\mathbf{y = 68}[/tex]

Hence, the acute angles are 22 and 68 degrees

Read more about acute angles at:

https://brainly.com/question/10388714