Answer: 1.38
Explanation:
Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.
[tex]P\propto T[/tex] (At constant volume and number of moles)
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 841 mm Hg
[tex]P_2[/tex] = final pressure of gas = ?
[tex]T_1[/tex] = initial temperature of gas =[tex]14.7^0C=(14.7+273)K=287.7K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]84.7^0C=(84.7+273)K=357.7K[/tex]
[tex]\frac{841}{287.7}=\frac{P_2}{357.7}[/tex]
[tex]P_2=1045.6mm Hg=1.38atm[/tex] ( 760 mm Hg = 1atm )
Thus the final pressure is 1.38
