Answer:
[tex]200 + 0.07m \leq 230[/tex]
A maximum of [tex]\approx[/tex] 428 miles is the distance what Divya can travel.
Step-by-step explanation:
Given that:
Rent to be paid for the car in the weekend = $200
Charges to be paid per mile = $0.07
Total money available with Divya = $230
To find:
The inequality as per her limitations and solution to the problem.
Solution:
Let the number of miles for which Divya can drive = [tex]m[/tex] miles
Charges for one mile = $0.07
Charges for [tex]m[/tex] miles = $0.07[tex]m[/tex]
Total charges for renting and [tex]m[/tex] miles = Rental charges + Operational charges
Total charges for renting and [tex]m[/tex] miles = $200 + $0.07[tex]m[/tex]
These are charges must be lesser than equal to the amount of money available with Divya.
Therefore, we can write:
[tex]200 + 0.07m \leq 230[/tex]
Subtracting 200 from both the sides:
[tex]0.07m \leq 30[/tex]
Dividing both sides with 0.07:
[tex]m \leq \dfrac{30}{0.07}\\m\leq 428.6[/tex]
Therefore, a maximum of [tex]\approx[/tex] 428 miles is the distance what Divya can travel.
