Answer: 0.0009 moles of octane were used up.
Explanation:
To calculate the moles :
[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]
Given mass of octane = 0.1 g
Molar mass of octane = 11.23 g/mol
Putting in the values we get:
[tex]\text{Moles of octane}=\frac{0.1g}{114.23g/mol}=0.0009moles[/tex]
Thus 0.0009 moles of octane were used up.