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A projectile is launched from ground level at an angle of 30.0° above horizontal with a speed of 10.0 m/s. If the projectile is moving over level ground, what is the maximum height above the ground that the projectile reaches?

Respuesta :

Answer:

Maximum height = 1.27 m

Explanation:

Given:

θ = 30°

Speed = 10 m/s

Find:

Maximum  height

Computation:

Maximum height = v²(sinθ)² / 2g

Maximum height = 10²(sin30)² / (2x9.81)

Maximum height = 1.27 m

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