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Prove that the vectors A = 2i - 3j + k and B = i+ j+ k are

mùtually perpendicular
​

Respuesta :

Answer:

theta = 90°

Explanation:

hope it's helpful

TheUnknownScientist

Explanation:

A • B = (2i - 3j + k) • (i + j + k)

= (2)(1) + (- 3)(1) + (1)(1)

= 0 = AB cos θ

∴ cos θ = 0 (as A ≠ 0,B ≠ 0)

or θ = 90°

or the vectors A and B are mutually perpendicular.

-TheUnknownScientist

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