Respuesta :
The particles present in the sample of ammonium carbonate are [tex]0.7826*10^{23}[/tex] particles. This can be calculated by using number of moles.
Number of moles:
It is defined as the given mass over molar mass.
Given mass= 12.7 g
Molar mass of ammonium carbonate= 96.06 g/mol
Number of moles = 12.7 g / 96.06 g/mol
Number of moles = 0.13 moles
One mole:
A mole is the amount (10) of material containing [tex]6.02214 * 10^{23}[/tex] particles.
1 mol = [tex]6.02214 * 10^{23}[/tex] particles
So, 0.13 moles = [tex]6.02214*10^{23}*0.13=0.7826*10^{23} \text{ particles}[/tex]
thus, there are [tex]0.7826*10^{23}[/tex] particles are present in 12.7 g of ammonium carbonate.
Find more information about One mole here:
brainly.com/question/1358482
