Consider the two triangles. Triangles A B C and H G I are shown. Angles A C B and H I G are right angles. The length of side A C is 15 and the length of side C B is 20. The length of side H I is 12 and the length of I G is 9. To prove that the triangles are similar by the SAS similarity theorem, it needs to be shown that

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Answer:

I think it's

D. AC/GI = BC/HI

Step-by-step explanation:

Angles that are congruent don't necessarily mean they're similar. But this is what I saw that is associated with similarity with triangles.

AC and GI are corresponding sides and BC and HI are corresponding sides as well so, yeah. D.

I think.

I guess.

I don't know.

I didn't pay attention, tbh. LOL

~Pengoon~

Lanuel

To prove that the triangles are similar based on the SAS similarity theorem, it needs to be shown that: AC/GI = BC/HI.

The properties of similar triangles.

In Geometry, two (2) triangles are said to be similar when the ratio of their corresponding side lengths are equal and their corresponding angles are congruent.

Based on the side, angle, side (SAS) similarity theorem, it needs to be shown that side AC/GI is equal to side BC/HI in order to prove that the triangles are similar.

Proof:

AC/GI = BC/HI

15/9 = 20/12

5/3 = 5/3.

Read more on similar triangles here: https://brainly.com/question/12960403

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Ver imagen Lanuel