Answer:
-9(-2/3)^{n-1}
Step-by-step explanation:
Given the sequence
-9,6,-4,8/3,-16/9
The sequence is a geometric progression. The nth term of a geometric progression is expressed as;
Tn = ar^{n-1}
a is the first term = -9
r is the common ratio = 6/-9 = -4/6 = -2/3
n is the number of terms
Substitute the given parameters into the formula;
Tn = -9(-2/3)^n-1
Hence the formula for the general term an of the sequence is -9(-2/3)^{n-1}
