Answer:
a) The gravitational acceleration at the surface of the Moon is g moon=1.67 m/s
2
The ratio of weights (for a given mass ) is the ratio of g-values, so
W
moon
=(100N)(1.67/9.8)=17N.
(b) For the force on that object caused by Earth's gravity to equal 17 N, then the free fall acceleration at its location must be
ag
=1.67m/s
2
. Thus , .
ag
= r 2
Gm
E
⇒
a
g
Gm
=1.5×10
7
m
So the object would need to be a distance of r/R
E
=2.4 "radii" from Earth's center.
Answer:
20 N
Explanation:
Consider that earth's acceleration due to gravity is approximately 9.81 m/s^2. Also consider that the moon's acceleration due to gravity is about 1.62 m/s^2. Using these two values, we can easily find the weight of the object on the moon, given that the object weighs 100 N, and that F = ma.
First, let's break it up.
100/9.81 =
10.193679918450561 kg
10.193679918450561*1.62 =
16.513761467889908 N
≈ 20 N (with one significant digit, since that is the least amount of sig figs in the problem)
