Answer:
145854.24J
Explanation:
Given parameters:
Specific heat capacity of water = 4.184J/g°C
Mass of the water = 700g
Initial temperature = 25.6°C
Final temperature = 75.4°C
Unknown:
Thermal energy = ?
Solution:
To solve this problem, we use the expression below;
H = m x c x Ф
H is quantity of heat
m is the mass
c is the specific heat capacity
Ф is the temperature change
H = 700 x 4.184 x (75.4 - 25.6) = 145854.24J
