Answer:
[tex] \huge \boxed {x = 1}[/tex]
Step-by-step explanation:
Both bases are the same so you will be able to solve the equation from exponent and exponent.
[tex]2x - 3 = - 2x + 1 \\ 2x + 2x = 1 + 3 \\ 4x = 4 \\ x = 1[/tex]
Answer Check
Substitute x = 1 in the equation.
[tex] {6}^{2(1) - 3} = {6}^{ - 2(1) + 1} \\ {6}^{2 - 3} = {6}^{ - 2 + 1} \\ {6}^{ - 1} = {6}^{ - 1} [/tex]
Both are same each sides. Therefore the equation is true.
