pls help me asap-
what is the length of segment FE?

Answer:
FE=√210=14.49.
Step-by-step explanation:
In right triangle EFH,angle EFH is 90°and FG is perpendicular to EH.
Therefore,
FE²= EG.EH
FE²=10×(10+11)
=10×21
FE²=210
FE= √210