Answer:
That can be reduced to:
[tex]4ab(6a)^{\frac{1}{2}}[/tex]
Step-by-step explanation:
What you need to do here is factor any perfect squares out of the out of the expression. That includes 16, a² and b². If you pull those out of the radical, they become 4, a and be respectively, leaving 6a inside the radical:
[tex](16a^36b^2)^{\frac{1}{2}}\\\\= \sqrt{16a^36b^2}\\\\= 4ab\sqrt{6a}[/tex]
or you can express that also as:
[tex]4ab(6a)^{\frac{1}{2}}[/tex]
