Answer:0.2167 m/s
Explanation:
Given
mass of brick M=8.5 kg
mass of toy truck m=6.5 kg
the velocity of truck u=0.5 m/s
Suppose v is the velocity after brick is landed on the truck
There is no external force acting so momentum is conserved
mu=(M+m)v
[tex]v=\dfrac{6.5}{15}\times 0.5\\v=0.2167\ m/s[/tex]