issaccamarena866
contestada

A particle moving at a velocity of 4.7 m/s
in the positive r direction is given an accel-
eration of 5.4 m/s in the positive y direction
for 0.1 s.
What is the final speed of the particle?

Respuesta :

quasarJose

Answer:

5.24m/s

Explanation:

Given parameters:

Initial velocity  = 4.7m/s

Acceleration  = 5.4m/s²

Time  = 0.1s

Unknown:

Final velocity of the particle = ?

Solution:

Acceleration is the rate of change of velocity with time.

   Acceleration  = [tex]\frac{v - u}{t}[/tex]  

v is the final velocity

u is the initial velocity

t is the time taken

  Now find v;

           5.4  = [tex]\frac{v - 4.7}{0.1}[/tex]  

             0.54  = v  - 4.7

          v  = 5.24m/s