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What are the zeros of the polynomial y = (3x − 1)(x + 2)(2x + 1)? (4 points) negative two comma negative start fraction one over two end fraction comma start fraction one over three end fraction negative two comma negative start fraction one over two end fraction comma negative start fraction one over three end fraction 3, −2, 2 two comma start fraction one over two end fraction comma negative start fraction one over three end fraction

Respuesta :

abidemiokin

Answer:

1/3, -2 and -1/2

Step-by-step explanation:

Given the polynomial function y = (3x − 1)(x + 2)(2x + 1)

The zeros of the function occurs at when y = 0

The expression becomes;

(3x − 1)(x + 2)(2x + 1) = 0

3x - 1 = 0

3x  = 1

x  = 1/3

Also

x = x+2

x = 0-2

x = -2

2x+ 1 = 0

2x = 0-1

2x = -1

x = -1/2

Hence the zeros of the polynomial are 1/3, -2 and -1/2

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