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A line passes through the points (-4, 8) and (3, -7).

Answer all parts of the question.

Part A: What is the slope of the line that passes through these points.

Part B: What is the equation of the line that passes through these points.

Part C: Where does the line intersect the x-axis and y-axis?

Respuesta :

chuity

Answer: (hope I got them correct)

A) -15/7

B) [tex]y=-\frac{15}{7}x-\frac{4}{7}[/tex]

C) It cuts the x-axis at (-4/15,0) and the y-axis at (0,-4/7).

Step-by-step explanation:

A) Slope = [8-(-7)]/(-4-3) = -15/7

B) Let [tex]y=-\frac{15}{7}x+c[/tex] be the required equation.

Substitute x=-4, y=8.

8=(-15/7)(-4)+c

c=-4/7

The equation is therefore [tex]y=-\frac{15}{7}x-\frac{4}{7}[/tex].

C) Substitute y=0, we will get x = -4/15 i.e. it cuts the x-axis at (-4/15,0).

Substitute x=0, we will get y = -4/7 i.e. it cuts the y-axis at (0,-4/7).

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