Answer:
[tex](s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39[/tex]
Step-by-step explanation:
Given functions are:
[tex]s(x)= x+6\\t(x)= 4x^2[/tex]
We have to find:
(s.t)(x) => this means we have to multiply the two functions to get the result.
So,
[tex](s.t)(x) = s(x)*t(x)\\= (x+6)(4x^2)\\=4x^2.x+4x^2.6\\=4x^3+24x^2[/tex]
Also we have to find
(s-t)(x) => we have to subtract function t from function s
[tex](s-t)(x) = s(x) - t(x)\\= (x+6) - (4x^2)\\=x+6-4x^2[/tex]
Also we have to find,
(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x
[tex](s+t)(x) = s(x)+t(x)\\= x+6+4x^2[/tex]
Putting x = -3
[tex]= -3+6+4(-3)^2\\=-3+6+4(9)\\=3+36\\=39[/tex]
Hence,
[tex](s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39[/tex]
