Answer:
[tex]F=683.790939[/tex]N
Explanation:
From the Question we are told that
Earth mass [tex]m_1= 5.98 * 10^2^4 kg[/tex]
Students mass [tex]m_2=70kg[/tex]
Distance of student from earth center Radius [tex]r=6.39 * 10^6 m[/tex]
Generally the equation for Force of attraction b/w the earth and the boy is mathematically given by
[tex]F=\frac{Gm_1m_2}{r^2}[/tex]
[tex]F=\frac{6.67.10^-^1^1*( 5.98 x 10^2^4)(70)}{(6.39 *10^6)^2}[/tex]
Therefore the force of attraction b/w the student and the earth is
[tex]F=683.790939N[/tex]
[tex]F\approx 684N[/tex]
