Answer:
0.05 = 5% probability that it will not be discovered
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Has an emergency locator
Event B: Not discovered
Probability of having an emergency locator:
70% of 75%(discovered).
100 - 89 = 11% of 100 - 75 = 25%(not discovered). So
[tex]P(A) = 0.7*0.75 + 0.11*0.25 = 0.5525[/tex]
Intersection of events A and B
Having an emergency locator and not discovered, so 11% of 25%
[tex]P(A \cap B) = 0.11*0.25 = 0.0275[/tex]
What is the probability that it will not be discovered?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0275}{0.5525} = 0.05[/tex]
0.05 = 5% probability that it will not be discovered