Answer:
0.094m
35,780N
Explanation:
1) Work done = 1/2ke^2
k is the spring constant = 335N/m
e is the extension
Workdone = 1.5J
Substitute
1.5 = 1/2*335*e^2
1.5 = 167.5e^2
e^2 = 1.5/167.5
e^2 = 0.00896
e = √0.00896
e = 0.094m
Hence the spring must be compressed by 0.094m
2) Workdone = 1/2Fe
F is the force = ?
Workdone = 3578Joules
extension e = 200mm = 0.2m
Substitute
3578 = 1/2*0.2F
3578 = 0.1F
F = 3578/0.1
F = 35,780N
Hence the force is 35,780N