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How many moles of HNO₃ will be produced from the reaction of 37.0 g of NO₂ with excess water in the following chemical reaction?
3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

Respuesta :

jzheng1229

Answer:

0.536 mol HNO₃

Explanation:

Step 1: Convert 37.0 g of NO₂ into mol NO₂:

37.0 g NO₂ x 1 mol NO₂/46.0 g NO₂ = 0.8043 mol NO₂

Step 2: Convert 0.8043 mol NO₂ into mol HNO₃:

0.8043 mol NO₂ x 2 mol HNO₃/3 mol NO₂ = 0.5362 mol HNO₃

Step 3: Round to 3 significant figures:

0.5362 mol HNO₃ -> 0.536 mol HNO₃

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