A number sequence has nth term 6n + 3 (a) Write down the first four terms of this sequence.  1st term ..............., 2nd term ..............., 3rd term ..............., 4th term

Whenever the value of 'n' is given in the form of an algebraic expression the common difference of the Arithmetic Progrsiion (A.P) is the coefficient of 'n' in the given expression.

Ex: In this Problem,

Given that n=6n+3

The coeeficient of 'n' is '6'

If you obsereve the answer you will also see that the Common difference is also '6'

MrRoyal MrRoyal · Answer 2 · 2021-09-21T12:21:48+02:00

A number sequence can either be arithmetic or geometric or neither.

The first 4 terms are 9, 15, 21 and 28

Given

[tex]T_n = 6n + 3[/tex]

First term

This means that n = 1.

So, we have:

[tex]T_1 = 6 \times 1 + 3[/tex]

[tex]T_1 = 6 + 3[/tex]

[tex]T_1 = 9[/tex]

Second term

This means that n = 2.

So, we have:

[tex]T_2 = 6 \times 2 + 3[/tex]

[tex]T_2 =12 + 3[/tex]

[tex]T_2 =15[/tex]

Third term

This means that n = 3.

So, we have:

[tex]T_3 = 6 \times 3 + 3[/tex]

[tex]T_3 = 18 + 3[/tex]

[tex]T_3 = 21[/tex]

Fourth term

This means that n = 4.

So, we have:

[tex]T_4 = 6 \times 4 + 3[/tex]

[tex]T_4 = 24 + 3[/tex]

[tex]T_4 = 27[/tex]

Hence, the first 4 terms are 9, 15, 21 and 28