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Required informationSkip to questionNOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.Find the sum and product of each of these pairs of numbers. Express your answers as base 3 expansions.The sum of the numbers (20001)3 and (1112)3 is ( )3 and their product is ( )3.

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Answer:

The answer is " [tex](21120)_3[/tex]  and [tex](100011112)_3[/tex]"

Step-by-step explanation:

Calculating the sum:

[tex]a= (20001)_3 \\\\b= (1112)_3[/tex]

[tex]\to a+b = 20001+1112[/tex]                     // 163+41=204

             [tex]=(21120)_3[/tex]

Explanation:

In the addition, first convert the given value (a,b) into decimal point that is (163, 41) and by adding its value is equal to (204) and after convert its value is equal to [tex](21120)_3[/tex].

Calculating the product:

[tex]a= (20001)_3 \\\\b= (1112)_3[/tex]

[tex]\to a*b = 20001*1112[/tex]                //  163 *41=6,683

             [tex]=(100011112)_3[/tex]

Explanation:

In the product calculation we convert the given value (a,b) into decimal point that is (163, 41) and multiplting its value which is equal to (6,683) and after convert its value is equal to [tex](100011112)_3[/tex].

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