Answer:
0.369 V
Explanation:
Given :
Capacitance ( c ) = 650 × 10–4 F
Charge ( q ) = 24 × 10–3 C
We are asked to find potential difference ( v )!
We know:
q = c v
= > v = q / c
Putting values here we get:
= > v = ( 24 × 10–3 ) / ( 650 × 10–4 ) V
= > v = 240 / 650 V
= > v = 24 / 65 V
= > v = 0.369 V
Therefore, potential difference between the plates is 0.369 V
