bak01761
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please help with Chem I DON'T HAVE ENOUGH TIME!
if a 119g sample of water was allowed to evaporate completely, what volume of water vapour would be produced in milliliters?​

Respuesta :

ak47232007

As 1 L = 1000 g

so 119 grams = 0.119000 L

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TheSection

We are given:

Mass of water: 119 grams

We know that one mole of a gas occupies 22.4L of volume

Number of moles of water:

Number of moles = given mass / Molar mass

Number of moles = 119 / 18             [molar mass of water = 18 grams/mol]

Number of moles = 6.61 moles

Volume occupied:

Volume = number of moles * 22.4 L

Volume = 6.61 * 22.4

Volume = 148L

Volume (in mL) = 1.48 * 10⁻¹ mL

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