Given the following equation x2 + 4x = 21 find the solutions. (Show All Work)


15a) Set the equation equal to 0 by inverse operations.




15b) Place the equation in factored form.




15c) Set each factor equal to 0 and solve for x.


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Respuesta :

Step-by-step explanation:

15a)

[tex]x^2+4x=21[/tex]               Subtract both sides by 21

[tex]x^2+4x-21 =0[/tex]

15b)

7 and -3 multiply to -21 and add to 4

The factors are (x+7)(x-3)

15c)

x+7 =0

x=-7  

x-3=0

x=3