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A right triangle has one leg that measures 7 inches and the hypotenuse measures 12 inches.
What is the length of the other leg?
Round your answer to the nearest hundredth.
Answer with a numeric value only. That is, do not include "in" or "inches" with your response.

Respuesta :

  • Hypotenuse=H=12in
  • Perpendicular=P=7in
  • Base=B=?

Using Pythagorean theorem

[tex]\boxed{\sf B^2=H^2-P^2}[/tex]

[tex] \\ \sf \longmapsto \: b = \sqrt{ {h}^{2} - {p}^{2} } \\ \\ \sf \longmapsto \: b = \sqrt{ {12}^{2} - {7}^{2} } \\ \\ \sf \longmapsto \: b = \sqrt{100 - 49} \\ \\ \sf \longmapsto \: b = \sqrt{51} \\ \\ \sf \longmapsto \: b = 7.2in[/tex]

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