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A weather balloon contains 9.7 moles of helium at a pressure of 0.955 atm and a temperature of 25 °C at ground level. What is the volume (in L) of the balloon under these conditions?

Respuesta :

dsdrajlin

Answer:

2.5 × 10² L

Explanation:

Step 1: Given and required data

  • Moles of He (n): 9.7 mol
  • Pressure (P): 0.955 atm
  • Temperature (T): 25 °C
  • Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Convert 25 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 25 + 273.15 = 298 K

Step 3: Calculate the volume (V) of the balloon

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 9.7 mol × (0.0821 atm.L/mol.K) × 298 K / 0.955 atm = 2.5 × 10² L

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