Respuesta :

Answer:

Answer is derived according to the procedure of calculating LCM of any two numbers

Step-by-step explanation:

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[tex]\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}[/tex]

[tex]x^2-y^2-1-2y \\\\x^2-(y^2+2y+1)\\\\x^2-(y+1)^2\\\\(x)^2-(y+1)^2\\\\(x+y+1)(x-y-1)[/tex]

[tex]\\\\[/tex]

[tex] y^2-1-x^2-2x\\\\y^2-(x^2+2x+1)\\\\y^2-(x+1)^2\\\\(y)^2-(x+1)^2\\\\(y+x+1)(y-x-1) [/tex]

According to the question,

we have to find the LCM

  • LCM=[tex]\sf{(x+y+1)(x-y-1)(y-x-1) }[/tex]