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Berta’s teacher, Ms. Rose Harper tells her class that when sixty consecutive odd integers are added together, their sum is 4800 and asks the class to determine the largest of the sixty integers. Help Berta get the answer!

Respuesta :

caylus

Answer:

Hello,

le largest is 139

Step-by-step explanation:

Since i am a lasy boy, i am going to calculate:

1+3+5+7+...+(1+2*59)   there are 60 numbers

=1+3+5+..+119

=60*(1+119)/2=30*120=3600 (not enough)

4800-3600=1200 are in rest.

1200/60=20 so we add 20 to each number:

21+23+25+27+...+139=4800

s1m1

Answer:

139

Step-by-step explanation:

Given: 60 consecutive odd integers added = 4800

if the first integer is x then the next integer will have 2 more to get the next odd integer ( for example 3, 5, 7... is 3, 3+2, 3+4)

        x,           x+2,             x+4 ,       x+6,.....      x+118

        x,           x+2*1 ,         x+ 2*2 ,  x+ 2*3 , .... x+2*59

first term, second term, ....                           , 60th term

Sum = [ number of terms(first term+last term) ] / 2

4,800 = [60 (x+x+118)] / 2, multiply both sides by 2

9,600 = 60 (2x+118) , divide both sides by 60

160 = 2x +118, subtract 118 from both sides of the equation

42 =2x , divide both sides by 2

21 = x, this is the smallest integer

the largest integer is the 60th term

x+118 = 21+118 = 139

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